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I have recently been on this board to try to get my badges, and I have done all the quizzes they offer, as well as a few ones more. I came across one that was pretty challenging, and managed to get a four-image out of a typical triple, and an image I made up entirely off the cuff. I wasn't sure how this was supposed to be done, but seeing that the difficulty level was a rather tough one, I decided that I needed some help from the experts. I came across this post, and thought of making an image up to put in the bottom row. Here is my question: I have taken my reputation almost all the way to 3000, and felt my skills were pretty strong. I also have more experience with StackExchange than with Facebook, so I figured I had an advantage. Does that account for my high-scores on the questions I already knew the answer to? What if I make another image in the bottom row, doesn't that nullify the previous answers? What would be the correct method to try and get a five, or would it be considered a special occasion? A: Does that account for my high-scores on the questions I already knew the answer to? Yes, it does. To add to that, sometimes you are only given hints that you should follow up on in order to get the answer (ie. Take the case of which version of IE is supported in which version of Windows, sometimes the answer is given as "Example 1.0.0", however, this is only a hint that in an earlier version of an example, the answer was "Example 1.0.1", or something like that). What if I make another image in the bottom row, doesn't that nullify the previous answers? No, it doesn't. In some cases, the question is not about what people would expect, but what you expect, and that doesn't necessarily have to be the easiest possible answer. In those cases, the expectation is not necessarily that the answers should be easy, but that the answers should be reasonable, and typically, getting out of your head what you expect isn't that difficult. What would be the correct method to try and get a five, or would it be considered a special occasion? Again, I would say What's New In? in{\mathcal{K}}^+_{{\mathbb{Q}}^{\mathrm{al}}}}(\delta_{{\mathfrak{m}}},\delta'_{{\mathfrak{m}}}))$ is invertible, so the result follows. [^1]: The idea behind all of this is that the 2-adic discoverer of arithmetic geometry, Serre, was too modest to see what was occurring in his own work. [^2]: The relevant connection between automorphic representations of ${\mathrm{GL}}_2/{\mathbb{Q}}$ and ${\mathrm{GL}}_2/{\mathbb{Q}}(j)$ will be spelled out later in our proof of Theorem \[mainthm\]. [^3]: For the purposes of this proof, we could easily replace by a simple bound of the form $C^n$ for arbitrary $C>0$, valid for large $n$. However, for the above proof, we need $C^n$ to go to infinity with $n$, and the approach of [@WBL] does not seem to give this. [^4]: In the notation of the introduction, write $F$ for a finite abelian extension of ${\mathbb{Q}}$ containing $K$, $E$ for a quadratic extension of $F$ contained in $K$, and $L = EK$. [^5]: In the old language of [@W1], a subgroup of a group $\operatorname{Gal}(L/{\mathbb{Q}})$ has the form $G_{L/{\mathbb{Q}}}$, the Galois group of the extension $L/{\mathbb{Q}}$. The relevant homomorphisms are of the form $H \rightarrow G_{L/{\mathbb{Q}}}$ given by restriction of automorphisms. [^6]: More specifically, this is the $p$-adic completion of a group with this property. 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